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  • Halogens: F2 (Z = 9), Cl2 (Z = 17), Br2 (Z = 35) and I2 (Z = 53).

    Halogens: F2 (Z = 9), Cl2 (Z = 17), Br2 (Z = 35) and I2 (Z = 53). Grade 10 SABIS ​

  • 5. Any reaction or process that consumes heat energy. Endothermic

    5. Any reaction or process that consumes heat energy. Endothermic Grade 10 SABIS SABIS

  • Chapter 8: Molecules in the Gas Phase

    < Back Chapter 8: Molecules in the Gas Phase Understand the behavior of molecules in the gas phase and how to describe their properties using the gas laws. Chapter 8: Molecules in the Gas Phase - This chapter explores the behavior of gases and the properties of the gas phase. Students will learn about the gas laws, the ideal gas law, and the kinetic molecular theory. The chapter also covers the behavior of gases in real-world situations. Previous Next

  • Chemical properties of Gp I - they all: react violently with Cl2(g) producing white solids, react vigorously with water to produce H2(g).

    Chemical properties of Gp I - they all: react violently with Cl2(g) producing white solids, react vigorously with water to produce H2(g). Grade 10 SABIS ​

  • Activation energy: definition in SABIS

    Activation energy: definition in SABIS Grade 10 SABIS ​ as activated complex (AC). The AC i activated complex s found at the highest point of the potential energy curve. It is an unstable structure with energy higher than both reactants and products.

  • Avogadro's number

    Avogadro's number ​ ​ 🔹 Definition: Avogadro's number is the number of particles (atoms, molecules, ions) present in one mole of any substance. It is approximately 6.02 × 10^23 particles per mole. 🧪🔢 By Italian chemist Amadeo Avogadro (1776-1856) ✨ Lesson: Avogadro's Number ✨ 🔬 Introduction: Avogadro's number is a crucial concept in chemistry that helps us bridge the gap between the microscopic world of atoms and molecules and the macroscopic world we observe. It allows us to quantify the vast number of particles in a substance and make meaningful calculations. Let's dive into Avogadro's number and its significance. 💡 Avogadro's Number: 🔹 Definition: Avogadro's number is the number of particles (atoms, molecules, ions) present in one mole of any substance. It is approximately 6.02 × 10^23 particles per mole. 🧪🔢 🧪 Significance of Avogadro's Number: ✅ Counting Particles: Avogadro's number provides a way to count and quantify the immense number of particles in a sample. It allows us to relate macroscopic quantities, such as mass and volume, to the microscopic realm of atoms and molecules. 📊🌌 ✅ Mole-to-Particle Conversion: Avogadro's number enables us to convert between the number of moles and the number of particles in a substance. It acts as a bridge between the macroscopic and microscopic scales. 🧪⚖️ ✅ Universal Constant: Avogadro's number is a fundamental constant in chemistry, similar to other constants like the speed of light or Planck's constant. It plays a central role in many calculations and theories. 🔬🌍 🔍 Example: Let's consider carbon-12, an isotope of carbon. One mole of carbon-12 contains exactly 6.02 × 10^23 carbon atoms. This means that in 12 grams of carbon-12, there are 6.02 × 10^23 atoms. The same applies to any other substance; one mole of any substance contains Avogadro's number of particles. 📏🧪🌱 🧪 Quiz (Basic Understanding): 1️⃣ What is Avogadro's number? a) The number of particles in one mole of a substance. b) The mass of one mole of a substance. c) The ratio of moles to particles in a substance. 2️⃣ What is the approximate value of Avogadro's number? a) 6.02 × 10^23 b) 3.14 c) 1.99 × 10^8 3️⃣ What does Avogadro's number allow us to do? a) Count and quantify the number of particles in a substance. b) Calculate the atomic mass of an element. c) Convert between temperature units. 4️⃣ How many atoms are there in one mole of a substance? a) 1 atom b) 6.02 × 10^23 atoms c) 10 atoms 🔍 Answers: 1️⃣ a) The number of particles in one mole of a substance. 2️⃣ a) 6.02 × 10^23 3️⃣ a) Count and quantify the number of particles in a substance. 4️⃣ b) 6.02 × 10^23 atoms 🌟 Fantastic! You've gained a basic understanding of Avogadro's number and its importance in chemistry. Embrace the vastness of the microscopic world and continue exploring the incredible realm of atoms and molecules! 🧪🔬✨

  • The Periodic table

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  • Iodine is shiny yet is a non-metal

    Iodine is shiny yet is a non-metal Grade 10 SABIS ​

  • Sum of masses of nucleons in a nucleus is different from nuclear mass

    Sum of masses of nucleons in a nucleus is different from nuclear mass Grade 10 SABIS ​ The sum of the masses of nucleons (protons and neutrons) in a nucleus is different from the nuclear mass. This distinction arises due to the concept of mass defect and the conversion of mass into energy, as described by Einstein's famous equation, E = mc^2. The sum of the masses of nucleons refers to the total mass of all protons and neutrons present in the nucleus of an atom. Each nucleon has a specific mass, which can be measured in atomic mass units (amu) or kilograms (kg). Adding up the individual masses of the nucleons gives us the total mass of the nucleus. However, when comparing the total mass of the nucleons to the actual nuclear mass, we observe a discrepancy. The nuclear mass is slightly lower than the sum of the masses of the individual nucleons. This phenomenon is known as mass defect. Mass defect occurs because the binding of nucleons in the nucleus involves the conversion of a small portion of mass into energy. According to Einstein's equation, the mass of a system is equivalent to the energy it contains. During the formation of the nucleus, some mass is converted into binding energy to hold the nucleons together. The binding energy, or the energy required to separate the nucleons in the nucleus, is released when the nucleus is formed. This energy contributes to the stability of the nucleus. Due to the conversion of mass into energy, the total mass of the nucleus is slightly less than the sum of the masses of the nucleons. The difference between the sum of the masses of nucleons and the nuclear mass is known as the mass defect. It represents the mass that has been converted into binding energy within the nucleus. The mass defect is typically measured in atomic mass units (amu) or kilograms (kg). The relationship between mass defect and binding energy is governed by Einstein's equation, E = mc^2. The mass defect corresponds to the energy released during the formation of the nucleus. It is directly proportional to the binding energy and can be calculated using the equation ΔE = Δmc^2, where ΔE represents the energy released and Δm represents the mass defect. The concept of mass defect and the conversion of mass into energy are fundamental in nuclear physics and have significant implications in various fields, including nuclear power generation, nuclear weapons, and understanding the stability and properties of atomic nuclei. In summary, the sum of the masses of nucleons in a nucleus is different from the nuclear mass due to the phenomenon of mass defect. The mass defect arises from the conversion of a small portion of mass into binding energy during the formation of the nucleus. This discrepancy reflects the release of energy and the stability of the nucleus. Understanding the distinction between the sum of nucleon masses and the nuclear mass is crucial in the study of atomic nuclei and nuclear processes.

  • Excess Reagent

    Excess Reagent Grade 10 SABIS SABIS The reactant that is present in a quantity greater than necessary to react with the limiting reagent.

  • Find heat involved with given mass of reactant/product from H

    Find heat involved with given mass of reactant/product from H Grade 10 SABIS ​ Finding the heat involved with a given mass of reactant or product from ΔH (enthalpy change) is an important aspect of thermochemistry. It allows us to determine the amount of heat transferred during a chemical reaction, based on the known enthalpy change and the mass of the reactant or product. The heat involved (q) can be calculated using the equation q = ΔH * m, where q represents the heat involved, ΔH is the enthalpy change, and m is the mass of the reactant or product. To use this equation, we need to know the value of ΔH, which can be obtained from experimental data or calculated using thermochemical equations. Additionally, we need to know the mass (m) of the reactant or product involved in the reaction. For example, let's consider the combustion of methane (CH4), where the enthalpy change (ΔH) is known to be -890 kJ/mol. If we have 10 grams of methane, we can calculate the heat involved as follows: q = ΔH * m = -890 kJ/mol * (10 g / 16 g/mol) = -556.25 kJ Therefore, in this case, the heat involved with 10 grams of methane in the combustion reaction is approximately -556.25 kJ. It's important to note that the sign of the enthalpy change (ΔH) indicates the direction of heat transfer. A negative ΔH value represents an exothermic reaction, where heat is released, while a positive ΔH value represents an endothermic reaction, where heat is absorbed. It's crucial to ensure that the units of enthalpy change (ΔH) and mass (m) are consistent in the calculation. If the enthalpy change is given in kilojoules per mole (kJ/mol), the mass should be in moles as well. By using the equation q = ΔH * m, we can determine the heat involved with a given mass of reactant or product in a reaction. This calculation allows us to understand the energy changes associated with chemical reactions and provides valuable insights into the heat flow within a system. In summary, finding the heat involved with a given mass of reactant or product involves using the equation q = ΔH * m, where q represents the heat involved, ΔH is the enthalpy change, and m is the mass of the reactant or product. By multiplying the enthalpy change by the mass, we can calculate the amount of heat transferred. Understanding and calculating the heat involved are essential in studying and analyzing energy changes in chemical reactions.

  • Chapter 1 Exercises Page 1 Exercise SABIS Grade 11

    < Back Chapter 1 Exercises Page 1 Exercise SABIS Grade 11 This is placeholder text. To change this content, double-click on the element and click Change Content. These are the exercises for Equilibrium SABIS Grade 11 Chemistry Part 1 Previous Next

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